SOLVED

21) Determine the rate law and the value of k for the following reaction using the data provided. S2O82?(aq) + 3 I?(aq) → 2 SO42?(g) + I3?(aq)[S2O82?]i (M)[I?]i (M)Initial Rate 0.300.424.54 0.440.426.65 0.440.213.33 A) Rate = 120 M-2s-1 [S2O82?]2[I?] B) Rate = 36 M-1s-1 [S2O82?][I?] C) Rate = 86 M-2s-1 [S2O82?][I?]2 D) Rate = 195 M-3s-1 [S2O82?]2[I?]2 E) Rate = 23 M-1/2s-1 [S2O82?][I?]1/2 22) Determine the rate law and the value of k for the following reaction using the data provided. NO2(g) + O3(g) → NO3(g) + O2(g)[NO2]i (M)[O3]i (M)Initial Rate 0.100.331.42 0.100.662.84 0.250.667.10 A) Rate = 1360 M-2.5s-1[NO2]2.5[O3] B) Rate = 227 M-2.5s-1[NO2][O3]2.5 C) Rate = 43 M-1s-1[NO2][O3] D) Rate = 430 M-2s-1[NO2]2[O3] E) Rate = 130 M-2s-1[NO2][O3]2 23) Determine the rate law and the value of k for the following reaction using the data provided. 2 NO(g) + O2(g) → 2 NO2(g)[NO]i (M)[O2]i (M)Initial Rate (M-1s-1) 0.0300.00558.55 x 10-3 0.0300.01101.71 x 10-2 0.0600.00553.42 x 10-2 A) Rate = 57 M-1s-1[NO][O2] B) Rate = 3.8 M-1/2s-1[NO][O2]1/2 C) Rate = 3.1 × 105 M-3s-1[NO]2[O2]2 D) Rate = 1.7 × 103 M-2s-1[NO]2[O2] E) Rate = 9.4 × 103 M-2s-1[NO][O2]2 24) Carbon-14 has a half-life of 5720 years and this is a first order reaction. If a piece of wood has converted 75% of the carbon-14, then how old is it? A) 11440 years B) 2375 years C) 4750 years D) 4290 years E) 1430 years 25) Carbon-14 has a half-life of 5720 years and this is a first order reaction. If a piece of wood has converted 25% of the carbon-14, then how old is it? A) 11440 years B) 2375 years C) 4750 years D) 4290 years E) 1430 years 26) Which of the following represents the integrated rate law for a first-order reaction? A) = – kt B) – = kt C) [A]t – [A]o = – kt D) k = Ae(-Ea/RT) E) = + lnA 27) Which of the following represents the integrated rate law for a second-order reaction? A) = – kt B) – = kt C) [A]t – [A]o = – kt D) k = Ae(-Ea/RT) E) =