SOLVED

51) Determine E°cell for the reaction: Pb + Zn2+ → Pb2+ + Zn. The half reactions are: Pb2+(aq) + 2 e- → Pb(s)E° = -0.125 V              Zn2+(aq) + 2 e- → Zn(s)E° = -0.763 V A) 0.638 V B) -0.638 V C) 0.888 V D) -1.276 V E) -0.888 V 52) Determine E°cell for the reaction: Pb + Cu2+ → Pb2+ + Cu. The half reactions are: Pb2+(aq) + 2 e- → Pb(s)E° = -0.125 V Cu2+ + 2 e- → CuE° = 0.340 V A) 0.215 V B) 0.465 V C) 0.930 V D) -0.215 V E) -0.465 V 53) Determine E°cell for the reaction: 2 Al3+ + 3 Zn → 2 Al + 3 Zn2+. The half reactions are: Al3+(aq) + 3 e- → Al(s)E° = -1.676 V              Zn2+(aq) + 2 e- → Zn(s)E° = -0.763 V A) 0.913 V B) -2.439 V C) 2.439 V D) -1.063 V E) -0.913 V 54) Determine E°cell for the reaction: 2 Ag + Mg2+ → 2 Ag+ + Mg. The half reactions are: Mg2+(aq) + 2 e- → Mg(s)E° = -2.356 V              Ag+(aq) + e- → Ag(s)E° = 0.800 V A) 0.756 V B) -0.756 V C) 3.156 V D) -3.156 V E) 1.556 V 55) Determine E°cell for the reaction: I2 + Cu → 2 I- + Cu2+. The half reactions are: I2(s) + 2 e- → 2 I-(aq)E° = +0.535 V Cu2+ + 2 e- → CuE° = 0.340 V A) 0.730 V B) -0.875 V C) 0.875 V D) 0.195 V E) -0.195 V 56) Determine E°cell for the reaction: Cl2 + 2 F- → 2 Cl- + F2. The half reactions are: F2(s) + 2 e- → 2 F-(aq)E° = +2.866 V Cl2(s) + 2 e- → 2 Cl-(aq)E° = 1.358 V A) 3.016 V B) -4.224 V C) 1.508 V D) 4.224 V E) -1.508 V 57) Determine E°cell for the reaction: MnO4- + 8 H+ + 5 Fe2+ → Mn2+ + 4 H2O + 5 Fe3+. The half reactions are: Fe3+(aq) + e- → Fe2+(aq)E° = +0.771 V MnO4-(aq) + 8 H+(aq) + 5 e- → Mn2+(aq) + 4 H2O(l)E° = 1.507 V A) -2.34 V B) -2.28 V C) 2.28 V D) -0.74 V E) 0.74 V 58) Will magnesium metal displace Al3+ ion from an aqueous solution? Mg2+(aq) + 2 e- → Mg(s)E° = -2.356 V Al3+(aq) + 3 e- → Al(s)E° = -1.676 V A) No, since E°cell is negative. B) Yes, since E°cell is negative. C) No, the reverse reaction is spontaneous. D) Yes, since E°cell is positive. E) No, the system is at equilibrium. Answer: D 59) Determine E°cell at 25 °C for the following reaction: Pb2+(aq) + Cu(s) → Cu2+(aq) + Pb(s) The half-reactions are: Pb2+(aq) + 2 e- → Pb(s)E° = -0.125 V Cu2+(aq) + 2 e- → Cu(s)E° = +0.337 V A) 0.212 V B) -0.462 V C) 0.462 V D) -0.212 V E) 0.424 V 60) Determine E°cell at 25°C for the following reaction: 3 Sn2+ + 2 Al(s) → 2 Al3+ + 3 Sn(s) Al3+ + 3 e- → Al(s)E° = -1.676 V Sn2+ + 2 e- → Sn(s)E° = -0.137 V A) 2.941 V B) -1.813 V C) 1.813 V D) -1.539 V E) 1.539 V