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61) The electron group geometry for XeF2 is ________. A) trigonal planar B) trigonal bipyramid C) bent D) linear E) trigonal pyramidal 62) On the average, air contains about 9.3 mL of argon per liter. What would be the partial pressure of argon in air when the barometric pressure is 780 torr? A) 84 torr B) 7.3 torr C) 780 torr D) 770 torr E) 790 torr 63) In a reaction between XeO3 and Mn2+ that occurred in 324 mL of solution, the gaseous Xe produced occupied a volume of 595 mL at STP. What is the molarity of the MnO4- solution resulting from the reaction? 9 H2O + 6 Mn2+ + 5 XeO3 → 6 MnO4- + 5 Xe + 18 H+ A) 0.0983 M B) 0.0683 M C) 0.00292 M D) 0.0820 M E) 0.00203 M 64) Write an equation for the oxidation in acid solution of Mn2+ to MnO4- by XeO3, which is reduced to Xe(g). A) 6 Mn2+ + 5 XeO3 → 6 MnO4- + 5 Xe B) 24 H2O + 6 Mn2+ + 5 XeO3 → 6 MnO4- + 5 Xe + 18 H+ C) H2O + Mn2+ + XeO3 → MnO4- + Xe + 2 H+ D) 24 H2O + 6 Mn2+ + 5 XeO3 + 30 H+ → 6 MnO4- + 5 Xe + 15 H2O + 48 H+ E) 9 H2O + 6 Mn2+ + 5 XeO3 → 6 MnO4- + 5 Xe + 18 H+ 65) If a certain natural gas supply contains 2.13% helium by mass, what amount of the natural gas must be processed, at 96.2% efficiency of helium recovery, to produce sufficient helium to inflate 24 party balloons to a volume of 5.3 L each at an internal gas pressure of 1.25 atm and a temperature of 23.7°C? A) 1.28 kg B) 1.18 kg C) 1.09 kg D) 0.82 kg E) 0.75 kg 66) The most reactive of the nonmetallic elements is ________. A) xenon B) nitrogen C) iodine D) helium E) fluorine 67) “Chlorine-type” laundry bleaches are in reality aqueous solutions of ________. A) NaOCl B) NaClO3 C) HOCl D) HOClO3 E) NaClO2 68) What is the formula for chloric acid? A) HClO B) HCl C) HClO3 D) HClO2 E) HClO4 69) What is the skeletal structure for chloric acid? A) H-O-Cl-O-O B) H-Cl-O-O C) H-O-O-Cl-O D) H-O-Cl-O E)O 70) Write the equation for commercially extracting bromine from seawater. A) Br2(l) + 2 Cl(aq) → Cl2(g) + 2 Br- B) 2 Br-(aq) + I2(g) → Br2(l) + 2 I-(aq) C) 4 Br-(aq) + Cl2(g) → Br2(l) + 2 BrCl(aq) D) 2 Br-(aq) + F2(g) → Br2(l) + 2 F-(aq) E) 2 Br-(aq) + Cl2(g) → Br2(l) + 2 Cl-(aq)

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